Diferencia entre revisiones de «1soin/ECA/UD2/01 Ariketa. Zirkuitu elektrikoak»

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'''1)'''
 
== 1) ==


<math>R_T = R_1+ R_2 + R_3 + R_4 -> R_T = 500+1000+1500+2000 = 5000 \Omega</math>
<math>R_T = R_1+ R_2 + R_3 + R_4 -> R_T = 500+1000+1500+2000 = 5000 \Omega</math>

Revisión del 08:42 4 nov 2016

1)

[math]\displaystyle{ R_T = R_1+ R_2 + R_3 + R_4 -\gt R_T = 500+1000+1500+2000 = 5000 \Omega }[/math]

[math]\displaystyle{ I = \frac{V}{R} = \frac{10}{5000} = 0,002A }[/math]

[math]\displaystyle{ P = \frac {V^2}{R} = \frac {10}{500} = 0,02W }[/math]

R1:

I1 =I

[math]\displaystyle{ V_1=I \cdot R=0.002 \cdot 500 = 1V }[/math]

[math]\displaystyle{ P_1 = \frac {V^2}{R} = \frac {1}{500} = 0,002W }[/math]

R2:

I2 =I

[math]\displaystyle{ V_2=I \cdot R=0.002 \cdot 1000 = 2V }[/math]

[math]\displaystyle{ P_2 = \frac {V^2}{R} = \frac {1}{1000} = 0,004W }[/math]

R3:

I3 =I

[math]\displaystyle{ V_3=I \cdot R=0.002 \cdot 1500 = 3V }[/math]

[math]\displaystyle{ P_3 = \frac {V^2}{R} = \frac {1}{1500} = 0,006W }[/math]

R4:

I4 =I

[math]\displaystyle{ V_4=I \cdot R=0.002 \cdot 2000= 4V }[/math]

[math]\displaystyle{ P_4 = \frac {V^2}{R} = \frac {1}{2000} = 0,008W }[/math]