Ver el código de «1soin/ECA/UD2/01 Ariketa. Zirkuitu elektrikoak»


== 1) ==

<math>R_T = R_1+ R_2 + R_3 + R_4 \Rightarrow R_T = 500+1000+1500+2000 = 5000 \Omega</math>

<math>I = \frac{V}{R} = \frac{10}{5000} = 0,002A</math>

<math>P = \frac {V^2}{R} = \frac {10}{500} = 0,02W</math>

R1:

I1 =I

<math>V_1=I \cdot R=0.002 \cdot 500 = 1V</math>

<math>P_1 = \frac {V^2}{R} = \frac {1}{500} = 0,002W</math>

R2:

I2 =I

<math>V_2=I \cdot R=0.002 \cdot 1000 = 2V</math>

<math>P_2 = \frac {V^2}{R} = \frac {1}{1000} = 0,004W</math>

R3:

I3 =I

<math>V_3=I \cdot R=0.002 \cdot 1500 = 3V</math>

<math>P_3 = \frac {V^2}{R} = \frac {1}{1500} = 0,006W</math>

R4:

I4 =I

<math>V_4=I \cdot R=0.002 \cdot 2000= 4V</math>

<math>P_4 = \frac {V^2}{R} = \frac {1}{2000} = 0,008W</math>

== 2) ==

Paraleloan jarritako zirkuituetan tentsioa konstantea jarraitzen da.

<math>R_T \Rightarrow \frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4} \Rightarrow \frac{1}{R_T} = \frac{1}{2000} + \frac{1}{2000} + \frac{1}{3000} + \frac{1}{3000} = \frac{10}{6000} \Rightarrow R_T = 600 \Omega</math>

<math>P = \frac{V^2}{R} \Rightarrow P = \frac{9^2}{600} =0,135W</math>

<math>I = \frac{V}{R} \Rightarrow I = \frac{9}{600} =0,015A</math>

==3)==

R<sub>2</sub> eta R<sub>3</sub>, haien artean paraleloan daudenez, hauen erresistentzia baliokidea kalkulatuko dugu, gero R<sub>1</sub>ekin egin behar diren kalkuluak errazteko.

<math>R_{23} \Rightarrow \frac{1}{R_{23}} = \frac{1}{R_2} + \frac{1}{R_3} \Rightarrow \frac{1}{R_{23}} = \frac{1}{1500} + \frac{1}{1000} = \frac{5}{3000} \Rightarrow R_{23} = 600 \Omega</math>

<math>R_T = 400 + 600 = 1000\Omega</math>

<math>I = \frac{V}{R} \Rightarrow I = \frac{10}{1000} = 0,01A</math>

R<sub>1</sub>:

I1=I

<math>V_1 = I_1 \cdot R_1 \Rightarrow V_1 = 0,01 \cdot 400 = 4V</math>

R<sub>23</sub>:

I<sub>23</sub>=I

<math>V_{23} = I_{23} \cdot R_{23} \Rightarrow V_{23} = 0,01 \cdot 600 = 6V</math>

R<sub>2</sub>:

<math>I_2 = \frac{V_2}{R_2} \Rightarrow I = \frac{6}{1500} = 0,004A</math>

R<sub>3</sub>:

<math>I_3 = \frac{V_3}{R_3} \Rightarrow I = \frac{6}{1000} = 0,006A</math>